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Potential in "Snow Globe Theory"

In "snow globe theory", a potential can be defined. It describes the relative change in the speed of light at great distances. The value is calculated from the change in length scale/change in time scale, i.e., P = 1/(1+T/R)². With Q = G·M, T = Q/c² is half the Schwarzschild radius (rs). The table shows the comparison in the solar system (T = 1476 m) with the Schwarzschild potential 1-rs/R. The red/blue shift at great distances with "snow globe theory" and the Newtonian potential E*-Q/R is calculated as N = T/R.

Planet Orbital Radius "SnowGlobe Theory" Potential Schwarzschild Potential Energetic Redshift
Unit Mio km 1/(1+T/R)² 1-2·T/R = 1-rs/R T/R
Neptune 4495 0.999999999343270 0.999999999343270 3.28365·10-10
Uranus 2871 0.999999998971787 0.999999998971787 5.14107·10-10
Saturn 1434 0.999999997941423 0.999999997941423 1.02929·10-9
Jupiter 778.5 0.999999996208093 0.999999996208092 1.89595·10-9
Mars 227.9 0.999999987046950 0.999999987046950 6.47652·10-9
Erth 149.6 0.999999980267380 0.999999980267380 9.86631·10-9
Venus 108.2 0.999999972717191 0.999999972717190 1.36414·10-8
Mercury 57.91 0.999999949024350 0.999999949024348 2.54878·10-8
Sun 0.696 0.999995758634182 0.999995758620690 2.12068·10-6
rs Sun 2.952·10-6 0.44444444444444.. 0 0.5

This potential can also be used in the Schwarzschild metric.
Unlike the Schwarzschild potential, it has no singularity for R other than 0. However, it uses the E-Q/R potential of Newtonian mechanics, which may only be asymptotically correct (for weak forces or large radii).** Otherwise, the event horizon (according to my definition) would always be at G·M/c² with local light speed and Newtonian gravity.
Derivation:
According to my definition, the event horizon would be the radius at which light is bent in a circle.
s = V0·t+(a/2)·t² s is the distance, V0 initial velocity = 0, a constant acceleration, t time.
The second derivative, say (here, the light path) curvature, of a parabola with equidistant h and radius of curvature rk is calculated as follows: 1/rk = (sleft+ sright-2·scenter)/h²
With a = Newtonian gravity = G·M/R², sleft = sright = 0, the light path h = c·t results in t -> 0:
R = rk = -G·M/c² for a circular light deflection. The negative sign comes from this: The acceleration is directed upward, the curvature downward.
Why upward? The (apparent) force is opposite to the acceleration. When I accelerate on my bicycle, inertia pushes me backward.
Note:
If a light beam travels perpendicularly from a stationary path, it is straight. From a moving object along the path, it appears slanted, and from an accelerating system, it appears curved. The Einstein elevator describes this for gravitational acceleration.
*Maximum potential energy, usually set to zero.
**The solution

Ludwig Resch